7x^2+4=235

Solution for 7x^2+4=235 equation:

7x^2+4=235

We move all terms to the left:

7x^2+4-(235)=0

We add all the numbers together, and all the variables

7x^2-231=0

a = 7; b = 0; c = -231;
Δ = b2-4ac
Δ = 02-4·7·(-231)
Δ = 6468
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6468}=\sqrt{196*33}=\sqrt{196}*\sqrt{33}=14\sqrt{33}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-14\sqrt{33}}{2*7}=\frac{0-14\sqrt{33}}{14}
=-\frac{14\sqrt{33}}{14}
=-\sqrt{33}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+14\sqrt{33}}{2*7}=\frac{0+14\sqrt{33}}{14}
=\frac{14\sqrt{33}}{14}
=\sqrt{33}
$